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Question: The root mean square velocity of an ideal gas in a closed container of fixed volume is increased fro...

The root mean square velocity of an ideal gas in a closed container of fixed volume is increased from 10×104 cm s110 \times 10 ^ { 4 } \mathrm {~cm} \mathrm {~s} ^ { - 1 }. Which of the following statement correctly explains how the change is accomplished.

A

By heating the gas, the temperature is doubled

B

By heating the gas, the pressure is quadrupled (i.e. made four times)

C

By heating the gas, the temperature is quadrupled

D

By heating the gas, the pressure is doubled

Answer

By heating the gas, the pressure is quadrupled (i.e. made four times)

Explanation

Solution

T1T2=(5×10410×104)2=14\therefore \frac { T _ { 1 } } { T _ { 2 } } = \left( \frac { 5 \times 10 ^ { 4 } } { 10 \times 10 ^ { 4 } } \right) ^ { 2 } = \frac { 1 } { 4 }