Question

The r.m.s. value of the alternating e.m.f. E = (8 sinω t + 6 sin 2ω t) V is

• A. 7.05 V
• B. 14.14 V
• C. 10 V
• D. 20 V

Answer 1

Answer: (A)

7.05 V

Answer 2

Peak value $V_{0} = \sqrt{(8)^{2} + (6)^{2}} = 10volt$ so

$v_{rms} = \frac{10}{\sqrt{2}} = 5\sqrt{2} = 7.05volt$.