Solveeit Logo

Question

Question: The rms speed of the molecules of a gas in the vessel is \(400m{{s}^{-1}}\) . If the temperature of ...

The rms speed of the molecules of a gas in the vessel is 400ms1400m{{s}^{-1}} . If the temperature of the gas is reduced to half then the rms speed of the remaining molecules will be ……….

Explanation

Solution

Temperature of the system is directly proportional to the rms velocity. The rms speed at a particular temperature is given to us. The ratio between the rms speed at temperature T and rms speed at temperature T/2 gives us the required answer.

Formula used: vrms=3RTM{{v}_{rms}}=\sqrt{\dfrac{3RT}{M}}

Complete step by step answer:
Measuring the velocities of particles at a given time results in a large distribution of values. Some particles may move very slowly, others very quickly, and because they are constantly moving in different directions, the velocity could equal zero. (Velocity is a vector quantity, equal to the speed and direction of a particle). To properly estimate the average velocity, average the squares of the velocities and take the square root of that value. This is known as the root-mean-square (RMS) velocity. We can represent the root mean square velocity by:
vrms=3RTM{{v}_{rms}}=\sqrt{\dfrac{3RT}{M}}
Where, R is the gas constant,
T is absolute temperature,
and M is the molar mass of the gas particles in kgmol1kgmo{{l}^{-1}} .
So any change in any of the variable parameters may lead to a change in vrms{{v}_{rms}} .
Let us only consider the temperature in the equation for this particular question.
From the equation, we can see that,
vrmsT{{v}_{rms}}\propto \sqrt{T} .
Now, let us assume that the temperature at which molecules having rms velocity equal to 400ms1400m{{s}^{-1}} as T.
Then, we need to find the rms velocity of the molecules when this temperature is made half.
i.e. TT2T\to \dfrac{T}{2} .
We know, vrmsT{{v}_{rms}}\propto \sqrt{T} and vrms{{v}_{rms}} at temperature T is 400ms1400m{{s}^{-1}}.
Then, vrms{{v}_{rms}} at temperature T2\dfrac{T}{2} could be found by,
400vrms=TT2 vrms=4002=282.84m/s \begin{aligned} & \dfrac{400}{{{v}_{rms}}}=\dfrac{\sqrt{T}}{\sqrt{\dfrac{T}{2}}} \\\ & \Rightarrow {{v}_{rms}}=\dfrac{400}{\sqrt{2}}=282.84m/s \\\ \end{aligned}

Therefore, the rms velocity of the molecules if temperature is reduced by half of the initial temperature is found to be 282.84m/s282.84m/s.

Note: In the similar manner, we can find the root mean square velocity of any sample gas at a particular temperature. We can square the root mean square velocity and use it to obtain the kinetic energy of the particles in the system.