Question

The r.m.s. speed of the molecules of a gas in a vessel is 400$ms^{- 1}$. If half of the gas leaks out, at constant temperature, the r.m.s. speed of the remaining molecules will be

• A. 800 $ms^{- 1}$
• B. $400\sqrt{2}ms^{- 1}$
• C. 400 $ms^{- 1}$
• D. 200 $ms^{- 1}$

Answer 1

Answer: (C)

400 $ms^{- 1}$

Answer 2

Since temperature is constant, so $v_{rms}$ remains same.