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Question: The right circular cylinder of radius \(r\) \(cm\) and height \(h\) \(cm\) ( where \(h > 2r\)) just ...

The right circular cylinder of radius rr cmcm and height hh cmcm ( where h>2rh > 2r) just encloses the sphere of diameter ( in cmcm):
A. rr
B. 2r2r
C. hh
D. 2h2h

Explanation

Solution

Draw the diagram and you will come to a relation between the diameter of the right circular cylinder and the sphere enclosed and then you will get your answer.

Complete step-by-step answer:
In this question it is said that there is the right circular cylinder of radius rr cmcm and height hh cmcm which just encloses the sphere and we need to find its diameter.
And it is also given that h>2rh > 2r.
So if any object needs to enclose others then their volume must be greater than the enclosed object volume.
So let us check
Volume of right circular cone \geqslant volume of the sphere enclosed.
Let radius of the sphere be RR
πr2h43πR3\pi {r^2}h \geqslant \dfrac{4}{3}\pi {R^3}
And it is also given that h>2rh > 2r.
Let us take h=2rh = 2r
Then πr2(2r)43πR3\pi {r^2}\left( {2r} \right) \geqslant \dfrac{4}{3}\pi {R^3}
2r343R32{r^3} \geqslant \dfrac{4}{3}{R^3}
R332r3{R^3} \leqslant \dfrac{3}{2}{r^3}
R(32)13rR \leqslant {\left( {\dfrac{3}{2}} \right)^{\dfrac{1}{3}}}r
Now let us draw the diagram of the right circular cylinder and the enclosed sphere.

As h>2rh > 2r, hence we can say that R=rR = r so that it encloses the sphere.
Now diameter is asked in the question which is twice the radius which is 2r2r.
Diameter = 2r2r

So, the correct answer is “Option B”.

Note: If we enclose the sphere into the right circular cylinder and it is given that h>2rh > 2r, then by observation also we can say that both have the same radius. Hence diameter will be 2r2r.