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Question: The resultant of the two vectors having magnitude 2 and 3 is 1. What is their cross product...

The resultant of the two vectors having magnitude 2 and 3 is 1. What is their cross product

A

6

B

3

C

1

D

0

Answer

0

Explanation

Solution

22+32+2×2×3×cosθ=1\sqrt{2^{2} + 3^{2} + 2 \times 2 \times 3 \times \cos\theta} = 1

By solving we get θ=180\theta = 180{^\circ}A×B=0\overrightarrow{A} \times \overrightarrow{B} = 0