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Question: The resonant frequency of a series LCR circuit with L=2.0 H,C=32\(\mu F\)and R=10\(\Omega\) is...

The resonant frequency of a series LCR circuit with L=2.0 H,C=32μF\mu Fand R=10Ω\Omega is

A

20Hz

B

30Hz

C

40Hz

D

50Hz

Answer

20Hz

Explanation

Solution

: Here, ,L=2H,C=32μF=32×106FR=10ΩL = 2H,C = 32\mu F = 32 \times 10^{- 6}FR = 10\Omega

ωr=1LC=12×32×106\therefore\omega_{r} = \frac{1}{\sqrt{LC}} = \frac{1}{\sqrt{2 \times 32 \times 10^{- 6}}} =10364=1038=125rads1= \frac { 10 ^ { 3 } } { \sqrt { 64 } } = \frac { 10 ^ { 3 } } { 8 } = 125 \mathrm { rads } ^ { - 1 } υr=ωr2π=1252×3.14=20Hz\upsilon_{r} = \frac{\omega_{r}}{2\pi} = \frac{125}{2 \times 3.14} = 20Hz