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Question: The resistive force on a very-high-velocity object of area A passing through a gas of density ρ at a...

The resistive force on a very-high-velocity object of area A passing through a gas of density ρ at a velocity v is

ForceArρsvt\sim A^{r}\rho^{s}v^{t} Then –

A

= 2, s = 1, t = 1\text{r } = \text{ 2, s } = \text{ 1, t } = \text{ 1}

B

= 2, s = 1, t = 2\text{r } = \text{ 2, s } = \text{ 1, t } = \text{ 2}

C

= 1, s = 1, t = 2\text{r } = \text{ 1, s } = \text{ 1, t } = \text{ 2}

D

= 1, s = 1, t = 1\text{r } = \text{ 1, s } = \text{ 1, t } = \text{ 1}

Answer

= 1, s = 1, t = 2\text{r } = \text{ 1, s } = \text{ 1, t } = \text{ 2}

Explanation

Solution

[F] = [A]r [ρ]s [v]t

MLT–2 = L2r Ms L–3s LtT–t = L2r+t–3s Ms T–t

equating the powers of each dimension give

2r + t – 3s = 1, s = 1, t = 2

i.e., r = 1; s = 1; t = 2