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Question: The resistance R =\(\frac{V}{i}\)where V= 100 \(\pm\)<!-- -->5 volts and i = 10 \(\pm\)<!-- -->0.2 a...

The resistance R =Vi\frac{V}{i}where V= 100 ±\pm5 volts and i = 10 ±\pm0.2 amperes. What is the total error in R

A

5%

B

7%

C

5.2%

D

52\frac{5}{2}%

Answer

7%

Explanation

Solution

R=VIR = \frac{V}{I} \therefore (ΔRR×100)ΔVVΔIImax{\left( \frac{\Delta R}{R} \times 100 \right)\frac{\Delta V}{V}\frac{\Delta I}{I}}_{\max}

=5100×100+0.210×100= \frac{5}{100} \times 100 + \frac{0.2}{10} \times 100 =(5+2)%= (5 + 2)\% = 7%