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Question

Physics Question on Current electricity

The resistance of the series combination of two resistances is SS. When they are joined in parallel through total resistance is PP. If S=nPS = nP, then the minimum possible value of nn is

A

4

B

3

C

2

D

1

Answer

4

Explanation

Solution

Let resistances be R1R_1 and R2R_2 So, S=R1+R2S = R_1 + R_2; P=R1R2R1+R2P = \frac{R_{1}R_{2}}{R_{1}+R_{2}} S=nPS = nP R1+R2=nR1R2R1+R2R_{1}+R_{2} = \frac{nR_{1}R_{2}}{R_{1}+R_{2}} (R1+R2)2=nR1R2\left(R_{1}+R_{2}\right)^{2} = nR_{1}R_{2} If R1=R2R_{1} = R_{2}, so minimum value of n=4.n = 4.