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Question

Physics Question on Current electricity

The resistance of the platinum wire of a platinum resistance thermometer at the ice point is 5Ω5\,\Omega and at steam point is 5.23Ω5.23\,\Omega . When the thermometer is inserted in a hot bath, the resistance of the platinum wire will be 5.795Ω5.795\,\Omega . Calculate the temperature of the bath.

A

3.456C3.456\,^{\circ}C

B

34.565C34.565\,^{\circ}C

C

345.65C345.65\,^{\circ}C

D

45.65C45.65\,^{\circ}C

Answer

345.65C345.65\,^{\circ}C

Explanation

Solution

R0=5Ω,R100=5.23Ω,Rt=5.795ΩR_{0}=5\,\Omega , R_{100}=5.23\, \Omega, R_{t}=5.795\,\Omega α=R100R0R0×100=RtR0R0×t\alpha=\frac{R_{100}-R_{0}}{R_{0}\times100}=\frac{R_{t}-R_{0}}{R_{0}\times t} Therefore,t=RtR0R100R0×100Therefore, t=\frac{R_{t}-R_{0}}{R_{100}-R_{0}}\times100 =(5.79555.235)×100=\left(\frac{5.795-5}{5.23-5}\right)\times100 =345.65C=345.65\,^{\circ} C