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Question: The resistance of decimolar solution of NaCl is 30 ohms. Calculate the conductivity of solution if t...

The resistance of decimolar solution of NaCl is 30 ohms. Calculate the conductivity of solution if the cell constant is 0.33 cm−1^{-1}.

A

0.025 Ω−1\Omega^{-1} cm−1^{-1}

B

0.035 Ω−1\Omega^{-1} cm−1^{-1}

C

0.011 Ω−1\Omega^{-1} cm−1^{-1}

D

0.029 Ω−1\Omega^{-1} cm−1^{-1}

Answer

0.011 Ω−1\Omega^{-1} cm−1^{-1}

Explanation

Solution

Given:

  • Resistance, R=30 ΩR = 30 \, \Omega
  • Cell constant, k=0.33 cm−1k = 0.33 \, \text{cm}^{-1}

The conductivity κ\kappa is given by:

κ=kR=0.3330=0.011 Ω−1cm−1\kappa = \frac{k}{R} = \frac{0.33}{30} = 0.011 \, \Omega^{-1} \text{cm}^{-1}