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Question

Physics Question on Current electricity

The resistance of a wire is R'R' ohm. If it is melted and stretched to n'n' times its original length, its new resistance will be :

A

Rn\frac{R}{n}

B

n2Rn^2 R

C

Rn2\frac{R}{n^2}

D

nRnR

Answer

n2Rn^2 R

Explanation

Solution

R2R1=l22l12\frac{R_{2}}{R_{1}} =\frac{l_{2}^{2}}{l_{1}^{2}}
=n2l12l12=\frac{n^{2} l_{1}^{2}}{l_{1}^{2}}
R2R1=n2\frac{R_{2}}{R_{1}} =n^{2}
R2=n2R1R_{2} =n^{2} R_{1}