Question

The resistance of a galvanometer is 90 ohms. If only 10 percent of the main current may flow through the galvanometer, in which way and of what value, a resistor is to be used

• A. 10 ohms in series
• B. 10 ohms in parallel
• C. 810 ohms in series
• D. 810 ohms in parallel

Answer 1

Answer: (B)

10 ohms in parallel

Answer 2

$i_{g} = 10\%$ of $i = \frac{i}{10}$⇒ $S = \frac{G}{(n - 1)} = \frac{90}{(10 - 1)} = 10\Omega$