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Question: The resistance of a galvanometer is 25 ohm and it requires \(50 \mu A\) for full deflection. The val...

The resistance of a galvanometer is 25 ohm and it requires 50μA50 \mu A for full deflection. The value of the shunt resistance required to convert it into an ammeter of 5 amp is

A

2.5×10−4ohm2.5 \times 10 ^ { - 4 } \mathrm { ohm }

B

1.25×10−3ohm1.25 \times 10 ^ { - 3 } \mathrm { ohm }

C

0.05 ohm

D

2.5 ohm

Answer

2.5×10−4ohm2.5 \times 10 ^ { - 4 } \mathrm { ohm }

Explanation

Solution

S=Giig−1=25550×10−6−1S = \frac { G } { \frac { i } { i _ { g } } - 1 } = \frac { 25 } { \frac { 5 } { 50 \times 10 ^ { - 6 } } - 1 } =25105−1=25105=2.5×10−4Ω= \frac { 25 } { 10 ^ { 5 } - 1 } = \frac { 25 } { 10 ^ { 5 } } = 2.5 \times 10 ^ { - 4 } \Omega