Solveeit Logo

Question

Physics Question on Resistance

The resistance of a field coil measures 50Ω\Omega at 20?C and 65Ω\Omega at 70?C. The temperature coefficient of resistance is

A

0.0086/?C

B

0.0068/?C

C

0.0096/?C

D

0.0999/?C

Answer

0.0068/?C

Explanation

Solution

The value of temperature coefficient of resistance is given by
α=R2R1R1(t2t1)=655050(7020)\alpha=\frac{R_2-R_1}{R_1(t_2-t_1)}=\frac{65-50}{50(70-20)}
(t1(t_1 and t2t_2 are in ?C)
α=1550?50=0.006/?C\Rightarrow \alpha=\frac{15}{50?50}=0.006/?C