Question
Physics Question on Current electricity
The resistance of a bulb filament is 100Ω at a temperature of 100?C. If its temperature coefficient of resistance be 0.005 per ?C, its resistance will become 200Ω at a temperature of:
A
300?C
B
400?C
C
500?C
D
200?C
Answer
400?C
Explanation
Solution
Let resistance of bulb filament is R0 at 0?C then from expression Rθ=R0[1+αΔθ] we have, 100=R0[1+0.005×100] and 200=R0[1+0.005×x] where x is temperature in ?C at which resistance become 200Ω. Dividing the above two equations 100200=1+0.005×1001+0.005x⇒x=400?C