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Question

Physics Question on Current electricity

The resistance of a bulb filament is 100Ω100\, \Omega at a temperature of 100?C100^?C. If its temperature coefficient of resistance be 0.0050.005 per ?C^?C, its resistance will become 200Ω200\,\Omega at a temperature of:

A

300?C300^?C

B

400?C400^?C

C

500?C500^?C

D

200?C200^?C

Answer

400?C400^?C

Explanation

Solution

Let resistance of bulb filament is R0R_0 at 0?C0^?C then from expression Rθ=R0[1+αΔθ]R_{\theta}=R_{0}\left[1+\alpha\Delta\theta\right] we have, 100=R0[1+0.005×100]100=R_{0}\left[1+0.005\times100\right] and 200=R0[1+0.005×x]200=R_{0}\left[1+0.005\times x\right] where xx is temperature in ?C^?C at which resistance become 200Ω200\,\Omega. Dividing the above two equations 200100=1+0.005x1+0.005×100x=400?C\frac{200}{100}=\frac{1+0.005x}{1+0.005\times100} \Rightarrow x=400^?C