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Question: The resistance of 0.01 N solution of an electrolyte was found to be 210 Ohm at 298 K, using a conduc...

The resistance of 0.01 N solution of an electrolyte was found to be 210 Ohm at 298 K, using a conductivity cell of cell constant 0.66cm−1.0.66cm^{- 1}. The specific conductance of solution is,

A

3.14×10−3mhocm−13.14 \times 10^{- 3}mhocm^{- 1}

B

3.14×10−3mho−1cm3.14 \times 10^{- 3}mho^{- 1}cm

C

3.14mhocm−13.14mhocm^{- 1}

D

3.14mho−1cm−13.14mho^{- 1}cm^{- 1}

Answer

3.14×10−3mhocm−13.14 \times 10^{- 3}mhocm^{- 1}

Explanation

Solution

κ=1R×la=1210×0.66=3.14×10−3mhocm−1.\kappa = \frac{1}{R} \times \frac{l}{a} = \frac{1}{210} \times 0.66 = 3.14 \times 10^{- 3}mhocm^{- 1}.