Question

The resistance of $0.01 \,m \,KCl$ solution at $298\, K$ is $1500\, \Omega$. If the conductivity of $0.01\, m \,KCl$ solution at $298\, K$ is $0.146 \,\times \,10^{-3}\, S \,cm ^{-1} .$ The cell constant of the conductivity cell in $cm ^{-1}$ is

• A. 0.219
• B. 0.291
• C. 0.301
• D. 0.194

Answer 1

Answer: (A)

0.219

Answer 2

$\kappa=\frac{1}{ R }\left(\frac{l}{ a }\right)$ $\therefore \frac{l}{ a }=\kappa \cdot R$ $=0.146 \times 10^{-3} \times 1500$ $=219 \times 10^{3}=0.219\, cm ^{-1}$