Question
Question: The resistance if a wire is 'R' ohm. If it is melted and stretched to 'n' times its original length,...
The resistance if a wire is 'R' ohm. If it is melted and stretched to 'n' times its original length, its new resistance will be:
(A) n2R
(B) nR
(C) nR
(D) n2R
Solution
Hint Given that the resistance of wire R has an initial length l1 and is stretched n times to new length l2. It is observed that there is no change in radius. This means, assume volume is constant. Find a relation between areas of the wire before and after extension and substitute it in the resistance formula R=Aρl.
Complete Step By Step Solution
It is given that there is a wire of radius r, length l1 having a resistance R. Now this wire is said to be extended to a new length l2, which is n times l1. Since , there is no change in radius of the wire, let us assume that the volume before and after stretching are constant.
V1=V2, where V1 is volume before stretching and V2is volume after stretching.
Now we know that volume is a product of area and height. In our case, height is the length of the wire
A1×l1=A2×l2
We know that , l2=n×l1. Substituting this , we get
⇒A1×l1=A2×n×l1
⇒nA1=A2
We know that resistance R of a material is calculated by using the formulaR=Aρl, where ρis represented as resistivity of the material , A is area and lis length of the wire.
Now , before extension , resistivity is given as , R1=A1ρl1
After extension, resistivity is given as, R2=A2ρl2
Substituting for A2in the equation forR2, we get
⇒R2=A1ρl2×n
Now substitutingl2=n×l1, we get
⇒R2=A1ρl1×n2
(The term A1ρl1is equal toR1 and R1 value given in the question is R)
⇒R2=R×n2
Thus, Option (d) is the right answer for the given question.
Note Electrical resistivity is defined as the electrical property of a material which defines its strength to oppose electric current.