Solveeit Logo

Question

Question: The resistance if a wire is 'R' ohm. If it is melted and stretched to 'n' times its original length,...

The resistance if a wire is 'R' ohm. If it is melted and stretched to 'n' times its original length, its new resistance will be:
(A) Rn2\dfrac{R}{{{n^2}}}
(B) nRnR
(C) Rn\dfrac{R}{n}
(D) n2R{n^2}R

Explanation

Solution

Hint Given that the resistance of wire R has an initial length l1{l_1} and is stretched n times to new length l2{l_2}. It is observed that there is no change in radius. This means, assume volume is constant. Find a relation between areas of the wire before and after extension and substitute it in the resistance formula R=ρlAR = \dfrac{{\rho l}}{A}.

Complete Step By Step Solution
It is given that there is a wire of radius r, length l1{l_1} having a resistance R. Now this wire is said to be extended to a new length l2{l_2}, which is n times l1{l_1}. Since , there is no change in radius of the wire, let us assume that the volume before and after stretching are constant.
V1=V2{V_1} = {V_2}, where V1{V_1} is volume before stretching and V2{V_2}is volume after stretching.
Now we know that volume is a product of area and height. In our case, height is the length of the wire
A1×l1=A2×l2{A_1} \times {l_1} = {A_2} \times {l_2}
We know that , l2=n×l1{l_2} = n \times {l_1}. Substituting this , we get
A1×l1=A2×n×l1\Rightarrow {A_1} \times {l_1} = {A_2} \times n \times {l_1}
A1n=A2\Rightarrow \dfrac{{{A_1}}}{n} = {A_2}
We know that resistance R of a material is calculated by using the formulaR=ρlAR = \dfrac{{\rho l}}{A}, where ρ\rho is represented as resistivity of the material , AA is area and llis length of the wire.
Now , before extension , resistivity is given as , R1=ρl1A1{R_1} = \dfrac{{\rho {l_1}}}{{{A_1}}}
After extension, resistivity is given as, R2=ρl2A2{R_2} = \dfrac{{\rho {l_2}}}{{{A_2}}}
Substituting for A2{A_2}in the equation forR2{R_2}, we get
R2=ρl2×nA1\Rightarrow {R_2} = \dfrac{{\rho {l_2} \times n}}{{{A_1}}}
Now substitutingl2=n×l1{l_2} = n \times {l_1}, we get
R2=ρl1×n2A1\Rightarrow {R_2} = \dfrac{{\rho {l_1} \times {n^2}}}{{{A_1}}}
(The term ρl1A1\dfrac{{\rho {l_1}}}{{{A_1}}}is equal toR1{R_1} and R1{R_1} value given in the question is RR)
R2=R×n2\Rightarrow {R_2} = R \times {n^2}

Thus, Option (d) is the right answer for the given question.

Note Electrical resistivity is defined as the electrical property of a material which defines its strength to oppose electric current.