Question

The relative humidity on a day when partial pressure of water vapour is $0.012 \times 10^{5} Pa$ at $12^{\circ} C$ is (Take vapour pressure of water at this temperature as $0.016 \times 10^{5}Pa)$

• A. 70%
• B. 40%
• C. 75%
• D. 25%

Answer 1

Answer: (C)

75%

Answer 2

Given,
Partial pressure of water vapour $=0.125 \times 10^{5} Pa$
Vapour pressure of water $=0.016 \times 10^{5} Pa$
Relative humidity at a given temperature $(R)$
$=\frac{\text { Partial pressure of } \text { water } \text { vapour }}{\text { vapour pressure of water }}$
$=\frac{0.125 \times 10^{5}}{0.016 \times 10^{5}}$
$=0.75$
$=75 \%$