Question
Question: The relative density of mercury is 13.6, its density in the S.I unit is given as \(X \times {10^3}kg...
The relative density of mercury is 13.6, its density in the S.I unit is given as X×103kgm−3. Find X.
(A) 13
(B) 14
(C) 13.6
(D) 14.6
Solution
Relative density is a dimensionless quantity and it denotes the ratio of density of a material with the density of water in any system of units. The density of water in the CGS system of units is 1 grams per cubic centimeters.
Complete step by step solution:
Since the relative density is the ratio of density of a material and density of water. The relative density of mercury can be written as
RDmercury=dwaterdmercury ,
Where dmercury denotes density of mercury and water denotes density of water,
Putting the value of dwater=1g/cm3, and given value of RDmercury=13.6, we get
13.6=1g/cm3dmercury,
Cross multiplication gives
dmercury=cm313.6g,
Converting grams to Kilograms by using 1g=10−3Kg ,
And centimeters into meters using 1cm=10−2m , we get
dmercury=(10−2m)313.6×10−3Kg,
This gives dmercury=10−6m313.6×10−3Kg,
Using the exponents of 10, dmercury=m313.6×106−3Kg,
Therefore, dmercury=m313.6×103Kg,
dmercury=13.6×103Kgm−3.
The density in SI units as mentioned in the question was X×103kgm−3 , comparing it to the calculated result gives us
X=13.6 .
Therefore, the correct answer to the question is option : C
Note: Alternately, if one knew the density of water in SI units to be 103kgm−3, it could have been used in the formula of relative density to calculate the density of mercury in a more easy manner.
Similarly another term that is used in place of relative density is specific gravity, Specific gravity is also a dimensionless quantity and it also denotes the ratio of density of a material with the density of water in any system of units.