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Question: The relative density of mercury is 13.6, its density in the S.I unit is given as \(X \times {10^3}kg...

The relative density of mercury is 13.6, its density in the S.I unit is given as X×103kgm3X \times {10^3}kg{m^{ - 3}}. Find X.
(A) 13
(B) 14
(C) 13.6
(D) 14.6

Explanation

Solution

Relative density is a dimensionless quantity and it denotes the ratio of density of a material with the density of water in any system of units. The density of water in the CGS system of units is 1 grams per cubic centimeters.

Complete step by step solution:
Since the relative density is the ratio of density of a material and density of water. The relative density of mercury can be written as
RDmercury=dmercurydwaterR{D_{mercury}} = \dfrac{{{d_{mercury}}}}{{{d_{water}}}} ,
Where dmercury denotes density of mercury and water denotes density of water,
Putting the value of dwater=1g/cm3{d_{water}} = 1g/c{m^3}, and given value of RDmercury=13.6R{D_{mercury}} = 13.6, we get
13.6=dmercury1g/cm313.6 = \dfrac{{{d_{mercury}}}}{{1g/c{m^3}}},
Cross multiplication gives
dmercury=13.6gcm3{d_{mercury}} = \dfrac{{13.6g}}{{c{m^3}}},
Converting grams to Kilograms by using 1g=103Kg1g = {10^{ - 3}}Kg ,
And centimeters into meters using 1cm=102m1cm = {10^{ - 2}}m , we get
dmercury=13.6×103Kg(102m)3{d_{mercury}} = \dfrac{{13.6 \times {{10}^{ - 3}}Kg}}{{{{({{10}^{ - 2}}m)}^3}}},
This gives dmercury=13.6×103Kg106m3{d_{mercury}} = \dfrac{{13.6 \times {{10}^{ - 3}}Kg}}{{{{10}^{ - 6}}{m^3}}},
Using the exponents of 10, dmercury=13.6×1063Kgm3{d_{mercury}} = \dfrac{{13.6 \times {{10}^{6 - 3}}Kg}}{{{m^3}}},
Therefore, dmercury=13.6×103Kgm3{d_{mercury}} = \dfrac{{13.6 \times {{10}^3}Kg}}{{{m^3}}},
dmercury=13.6×103Kgm3{d_{mercury}} = 13.6 \times {10^3}Kg{m^{ - 3}}.
The density in SI units as mentioned in the question was X×103kgm3X \times {10^3}kg{m^{ - 3}} , comparing it to the calculated result gives us
X=13.6X = 13.6 .

Therefore, the correct answer to the question is option : C

Note: Alternately, if one knew the density of water in SI units to be 103kgm3{10^3}kg{m^{ - 3}}, it could have been used in the formula of relative density to calculate the density of mercury in a more easy manner.
Similarly another term that is used in place of relative density is specific gravity, Specific gravity is also a dimensionless quantity and it also denotes the ratio of density of a material with the density of water in any system of units.