Question

The relationship between the force $F$ and position $x$ of a body is as shown in figure. The work done in displacing the body from $x = 1 \, m$ to $x = 5 \, m$ will be :

• A. 30 J
• B. 15 J
• C. 25 J
• D. 20 J

Answer 1

Answer: (B)

15 J

Answer 2

Work done = area enclosed by $F-x$ graph
= area of $ABNM$ + area of $CDEN$ - area of $EFGH$ + area of $HIJ$
$= 1 \times 10 + 1 \times 5 + \frac{1}{2} \times 1 \times 10$
$= 10 + 5 - 5 + 5 = 15\, J$