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Question

Physics Question on work, energy and power

The relationship between the force FF and position xx of a body is as shown in the figure. The work done in displacing the body from x=1mx = 1\,m to x=5mx = 5\,m will be

A

30 J

B

15 J

C

25 J

D

20 J

Answer

20 J

Explanation

Solution

W=W = area under FxF - x graph
From X=0X =0 to X=1X =1, force and displacement both are positive. Therefore work done is positive.
W0=+ Area =+5J W _{0}=+\text { Area }=+5 J
From X=1X =1 to X=3X =3, force and displacement both are positive. Therefore work done is positive.
W1=+ Area =+15J W _{1}=+\text { Area }=+15 J
From X=3X =3 to X=4X =4, force is negative but displacement is positive. Therefore work done is again positive.
W2= Area =5J \therefore W _{2}=-\text { Area }=-5 J
From X=4X =4 to X=5X =5, force and displacement both are positive. Therefore work done is again positive.
$
\therefore W _{3}=+\text { Area }=+5 J \\
W _{\text {Total }}= W _{0}+ W _{1}+ W _{2}+ W _{3}=20 J

$