Question

The relationship between standard reduction potential of cell and equilibrium constant is shown by.

• A. $E_{mg^{2 +}|Mg}vs\log\lbrack Mg^{2 +}\rbrack$
• B. $E_{Mg^{2 +}|Mg} = Eº_{Mg^{2 +}|Mg} - \frac{0.059}{2}\log\frac{1}{\lbrack Mg^{2 +}\rbrack}$
• C. $E_{mg^{2 +}|Mg}vs\log\lbrack Mg^{2 +}\rbrack$
• D. $(E_{ext} < 1.1V)$

Answer 1

Answer: (B)

$E_{Mg^{2 +}|Mg} = Eº_{Mg^{2 +}|Mg} - \frac{0.059}{2}\log\frac{1}{\lbrack Mg^{2 +}\rbrack}$

Answer 2

$E_{\text{cell}}^{o} = \frac{2.303RT}{nF}\log K = \frac{0.0591}{n}\log K_{c}at298K$.