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Question

Chemistry Question on Thermodynamics

The relationship between equilibrium constant K and free energy change of the process is given by

A

ΔG=−RTlog⁡K\Delta G = -RT\log K

B

ΔG∘=RTlog⁡1K\Delta G\degree = RT\log \frac{1}{K}

C

ΔG∘=2RTlog⁡K\Delta G\degree = 2RT\log K

D

ΔG∘=2.303RTlog⁡K−1\Delta G\degree = 2.303RT\log K^{-1}

Answer

ΔG∘=2.303RTlog⁡K−1\Delta G\degree = 2.303RT\log K^{-1}

Explanation

Solution

The correct option is (D): ΔG∘=2.303RTlog⁡K−1\Delta G\degree = 2.303RT\log K^{-1}