Solveeit Logo

Question

Question: The relation S is defined on the set of integers Z as zSy if integer z divides integer y. Then. A...

The relation S is defined on the set of integers Z as zSy if integer z divides integer y. Then.
A) S in an equivalence relation
B) S is only reflexive and symmetric
C) S is only reflexive and transitive
D) S is only symmetric and transitive

Explanation

Solution

In this question, they have given us the relation between z and y is denoted by S and is defined as zSy. It means that z integer divided integer y.
We have to choose the correct option. If the relation S is reflexive, transitive as well as symmetric then relation S is called an equivalence relation. Check whether the relation S is reflexive or not, it is transitive or not and it is symmetric or not.

Complete step by step solution:
We have given the relation S which is defined on the set of integers Z as zSy which defines that integer z divides integer y.
First of all, check whether the relation S is reflexive or not. Reflexive means z is the same means both the integers are same i.e. Z=y. if we divide an integer by itself then it is always divisible.
zz=1\Rightarrow \dfrac{z}{z} = 1
zSz\Rightarrow zSzis true, as z always divides z.
So, S is reflexive relation
Now check whether S is symmetric or not. By Symmetry, it means if zSy is true then ySz is also true. Symmetry means it is defined when we interchange the integers.
yis not related toz\Rightarrow y\,\text{is not related to}\,z, as y doesn’t divide z.
Here, if z divides y then it is not necessary that y divides z e.g. 6 divides 48 but 48 doesn’t divide 6.
So, S is not symmetric.
Check for transitive: Transitive means that if we have three integers and the relation of them should exist i.e. if zSy and ySx exist then zSx also exists. Here, if z divides y and y divides x then z divides x also e.g. 2 divided 6 and 6 divides 48 and hence 2 divides 48.
zSy\Rightarrow zSy
ySx\Rightarrow ySx
zSx\Rightarrow zSxis true, as z also divides x.
So, S is a transitive relation.
In the end, it is concluded that S is only reflexive and transitive but not symmetric. So, it is not an equivalence relation.

Hence, option C is the correct answer.

Note:
An equivalence relation means if we have two elements and we have to identify whether they share a set of common attributes. So, when we talk about equality relation, equality satisfies the reflexive i.e. z=z for all values of z, transitive i.e. z=y implies y=z and symmetric i.e. z=y and y=x implies z=x properties.