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Question

Mathematics Question on Functions

The relation R =\\{(a, b) : \operatorname{gcd}(a, b)=1,2 a \neq b, a, b \in Z\\} is :

A

reflexive but not symmetric

B

transitive but not reflexive

C

symmetric but not transitive

D

neither symmetric nor transitive

Answer

neither symmetric nor transitive

Explanation

Solution

Reflexive:
(a,a)gcd  of(a,a)=1(a,a) ⇒ gcd \space of (a,a)=1
Which is not true for every aϵZ.a ϵ Z.

Symmetric:
Take a=2,b=1gcd(2,1)=1a=2, b=1⇒gcd(2,1)=1
Also 2a=4b2a=4\neq b
Now when a=1,b=2gcd(1,2)=1a=1,b=2⇒gcd(1,2)=1
Also now 2a=2=b2a=2=b
Hence a=2ba=2b
R is not Symmetric

**Transitive: **
Let a=14,b=19,c=21a=14,b=19,c=21
gcd (a,b)=1(a,b)=1
gcd (b,c)=1(b,c)=1
gcd (a,c)=7(a,c)=7
Hence not transitive

The correct option is (D): R is neither symmetric nor transitive.