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Question

Question: The relation between Y, \(\eta\) and B is...

The relation between Y, η\eta and B is

A

1Y=13η+19B\frac{1}{Y} = \frac{1}{3\eta} + \frac{1}{\text{9B}}

B

9Y=1η+3B\frac{9}{Y} = \frac{1}{\eta} + \frac{3}{B}

C

1η=1B+1Y\frac{1}{\eta} = \frac{1}{B} + \frac{1}{Y}

D

9Y+3η+1B\frac{9}{Y} + \frac{3}{\eta} + \frac{1}{B}

Answer

9Y+3η+1B\frac{9}{Y} + \frac{3}{\eta} + \frac{1}{B}

Explanation

Solution

: The relation between Y,ηY,\etaand B is

9Y=1B+3η\frac{9}{Y} = \frac{1}{B} + \frac{3}{\eta}

Where Y is Young’s modulus, B is Bulk modulus and η\etamodulus of rigidity.