Solveeit Logo

Question

Question: The relation between two specific heats of a gas is...

The relation between two specific heats of a gas is

A

CPCV=RJC_{P} - C_{V} = \frac{R}{J}

B

CVCP=RJC_{V} - C_{P} = \frac{R}{J}

C

CpCv=JC_{p} - C_{v} = J

D

CvCp=JC_{v} - C_{p} = J

Answer

CPCV=RJC_{P} - C_{V} = \frac{R}{J}

Explanation

Solution

When CPC_{P} and CVC_{V} are given with calorie and R with Joule then CPCV=R/JC_{P} - C_{V} = R/J.