Question

The relation between time and displacement for two particles is given by – y₁ = 0.06 sin 2p (0.04t+f₁),

y₂ = 0.03 sin 2p (0.04t+f₂)

The ratio of the intensity of the waves produced by the vibrations of the two particles will be –

• A. 2 :1
• B. 1 : 2
• C. 4 : 1
• D. 1 : 4

Answer 1

Answer: (C)

4 : 1

Answer 2

I µ a² , $\frac{I_{1}}{I_{2}} = \left( \frac{a_{1}}{a_{2}} \right)^{2} = \left( \frac{0.06}{0.03} \right)^{2} = 4:1$