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Question

Question: The relation between the linear magnification \(m\) the object distance \(f\) is...

The relation between the linear magnification mm the object distance ff is

A

m=fufm = \frac { f - u } { f }

B

m=ffum = \frac { f } { f - u }

C

m=f+ufm = \frac { f + u } { f }

D

m=ff+um = \frac { f } { f + u }

Answer

m=ffum = \frac { f } { f - u }

Explanation

Solution

1f=1v+1u\frac { 1 } { f } = \frac { 1 } { v } + \frac { 1 } { u }uf=uv+1\frac { u } { f } = \frac { u } { v } + 1

uv=1uf- \frac { u } { v } = 1 - \frac { u } { f } vu=ffu\Rightarrow \frac { - v } { u } = \frac { f } { f - u } so (,oa) m=ffum = \frac { f } { f - u }.