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Question

Physics Question on Waves

The relation between phase difference and path difference is

A

Δϕ=2πλ(Δx)\Delta\phi=\frac{2\pi}{\lambda}\left(\Delta x\right)

B

Δϕ=2πλ(Δx)\Delta\phi=2\pi\lambda\left(\Delta x\right)

C

Δϕ=2πλλ\Delta\phi=\frac{2\pi\lambda}{\lambda}

D

Δϕ=2Δxλ\Delta\phi=\frac{2\Delta x}{\lambda}

Answer

Δϕ=2πλ(Δx)\Delta\phi=\frac{2\pi}{\lambda}\left(\Delta x\right)

Explanation

Solution

Phase difference =2πλ×=\frac{2\pi}{\lambda} \times path difference Δϕ=2πλ×Δx\Delta\phi=\frac{2\pi}{\lambda}\times\Delta x