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Question

Physics Question on Transistors

The relation between α and β\alpha\,and\,\beta parameters of a transistor is given by

A

α=1+ββ\alpha=\frac{1+\beta}{\beta}

B

α=1−ββ\alpha=\frac{1-\beta}{\beta}

C

α=β1+β\alpha=\frac{\beta}{1+\beta}

D

α=β1−β\alpha=\frac{\beta}{1-\beta}

Answer

α=β1+β\alpha=\frac{\beta}{1+\beta}

Explanation

Solution

α\alpha and β\beta both are amplification factors IE=IC+IBI_{E}=I_{C}+I_{B} IEIC=1+IBIC\frac{I_{E}}{I_{C}}=1+\frac{I_{B}}{I_{C}} 1α=1+1β\frac{1}{\alpha }=1+\frac{1}{\beta } α=β1+β\alpha =\frac{\beta }{1 + \beta }