Question: The relation $3t = \sqrt{3x} + 6$ describes the displacement of a particle in one direction where ...

Question

The relation $3t = \sqrt{3x} + 6$ describes the displacement of a particle in one direction where $x$ is in metres and $t$ in sec. The displacement, when velocity is zero, is

Answer 1

Solution

$3t = \sqrt{3x} + 6 \Rightarrow 3x = (3t - 6)^{2}$

$\Rightarrow x = 3t^{2} - 12t + 12$

$v = \frac{dx}{dt} = 6t - 12$ , for $v = 0,\mspace{6mu} t = 2\sec$

$x = 3(2)^{2} - 12 \times 2 + 12 = 0$

Question: The relation \(3t = \sqrt{3x} + 6\) describes the displacement of a particle in one direction where ...

Solution