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Question

Physics Question on Refraction of Light

The refractive index of glass is 1.5201.520 for red light and 1.5251.525 for blue light. Let D1D_1, and D2D_2 be angles of minimum deviation for red and blue light respectively in a prism of this glass then,

A

D1<D2D_1 < D_2

B

D1=D2D_1 = D_2

C

D1D_1 can be less than or greater than D2D_2 depending upon the angle of prism

D

D1>D2D_1 > D_2

Answer

D1<D2D_1 < D_2

Explanation

Solution

Given : μR=1.520\mu_{R}=1.520, μB=1.525\mu_{B}=1.525 As, μ=sin(A+D2)sin(A2)\mu=\frac{sin \left(\frac{A+D}{2}\right)}{sin \left(\frac{A}{2}\right)} where A is the angle of prism, D is the angle of minimum deviation Here, $\mu_{R}