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Question: The reflection of the point \[\left( {6,8} \right)\] in the line \(x = y\) is A) \(\left( {4,2} \...

The reflection of the point (6,8)\left( {6,8} \right) in the line x=yx = y is
A) (4,2)\left( {4,2} \right)
B) (6,8)\left( { - 6, - 8} \right)
C) (8,10)\left( { - 8, - 10} \right)
D) (8,6)\left( {8,6} \right)

Explanation

Solution

Find the coordinates of the midpoint of the given point and the point of reflection. Substitute the value of mid-point in the given equation of line x=yx = y. Now, the product of the slope of line joining the points and the given line will be 1 - 1. Use this to find another equation in terms of coordinates of reflection. Solve the equations to find the coordinates of reflection.

Complete step by step solution:
Let the line x=yx = ybe ABABand the point P(6,8)P\left( {6,8} \right).
Let Q(h,k)Q\left( {h,k} \right) be the point of reflection of (6,8)\left( {6,8} \right) in the line x=yx = y
Line ABABacts like a mirror.
Then, P(6,8)P\left( {6,8} \right) and Q(h,k)Q\left( {h,k} \right) are at equal distances from the line x=yx = y
Let RRbe the mid-point of the line ABAB.
Then coordinates of RR are (h+62,k+82)\left( {\dfrac{{h + 6}}{2},\dfrac{{k + 8}}{2}} \right) from the mid-point formula.
Also, R(h+62,k+82)R\left( {\dfrac{{h + 6}}{2},\dfrac{{k + 8}}{2}} \right) lies on the line x=yx = y, it will satisfy the equation. This implies,
h+62=k+82 h+6=k+8 hk=2 (1)  \dfrac{{h + 6}}{2} = \dfrac{{k + 8}}{2} \\\ h + 6 = k + 8 \\\ h - k = 2{\text{ }}\left( 1 \right) \\\
Also, PQABPQ \bot AB, therefore, the product of slope of PQPQ and ABABis equals to 1 - 1.
Slope of ABAB=coefficient of xcoefficient of y - \dfrac{{{\text{coefficient of }}x}}{{{\text{coefficient of }}y}} which is 1
Hence, slope of PQPQ is 1 - 1 which is also equals to y2y1x2x1=k8h6\dfrac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}} = \dfrac{{k - 8}}{{h - 6}}
k8h6=1 k8=h+6 h+k=14 (2)  \dfrac{{k - 8}}{{h - 6}} = - 1 \\\ k - 8 = - h + 6 \\\ h + k = 14{\text{ }}\left( 2 \right) \\\
Solve equation (1) and (2) to find the value of (h,k)\left( {h,k} \right)
Add equation (1) and (2)
hk+h+k=2+14 2h=16 h=8  h - k + h + k = 2 + 14 \\\ 2h = 16 \\\ h = 8 \\\
Substitute the value of kkin equation (1)
8k=2 k=6  8 - k = 2 \\\ k = 6 \\\
Therefore, the reflection of the point (6,8)\left( {6,8} \right) in the line x=yx = y is (8,6)\left( {8,6} \right)

Hence, option D is correct.

Note:
The line x=yx = y passes through the origin. This question can alternatively be done by using the condition that the reflection of the point (x,y)\left( {x,y} \right) in the line x=yx = y is (y,x)\left( {y,x} \right). This implies that xx coordinate and the yy coordinate interchanges.