Question
Chemistry Question on Thermodynamics
The reduction potential of hydrogen half-cell will be negative if :
A
p(H2)=2atm and [H+]=2.0M
B
p(H2)=1atm and [H+]=2.0M
C
p(H2)=1atm and [H+]=1.0M
D
p(H2)=2atm and [H+]=1.0M
Answer
p(H2)=2atm and [H+]=1.0M
Explanation
Solution
H++e−⟶21H2 Apply Nernst equation E=0−10.059log[H+]PH221 E=−10.059log121/2 Therefore E is negative.