Question

The reduction potential of hydrogen electrode when placed in a buffer solution is found to be – 0.413V. The pH of the buffer is –

• A. 10
• B. 4
• C. 7
• D. 12

Answer 1

Answer: (C)

7

Answer 2

$\text{- 0.413 = 0 - 0 .059 log}\frac{1}{\left\lbrack H^{+} \right\rbrack}\text{ or = }\frac{\text{0.414}}{\text{0.059}}\text{- log }\text{H}^{+}\text{ = pHor } \text{pH = 7}$