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Question

Chemistry Question on Electrochemistry

The reduction potential (E0,in V)\left(E^0, in\ V\right) of MnO4(aq)/Mn(s)MnO _4^{-}( aq ) / Mn ( s ) is[Given:E(MnO4(aq)/MnO2(s))0=1.68V;E(MnO2(s)/Mn2+(aq))0=1.21V;E(Mn2(aq)/Mn(s))0=1.03V]\left[ Given : E_{\left( MnO _4^-( aq ) / MnO _2( s )\right)}^0=1.68 V ; E_{\left( MnO _2( s )/ Mn ^{2+}( aq )\right)}^0=1.21 V ; E_{\left( Mn ^2( aq ) / Mn ( s )\right)}^0=-1.03 V \right]

Answer

Answer: 0.77