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Question: The reduce mass of two particles having masses *m* and *2 mis*...

The reduce mass of two particles having masses m and 2 mis

A

2 m

B

3 m

C

2m3\frac{2m}{3}

D

m2\frac{m}{2}

Answer

2m3\frac{2m}{3}

Explanation

Solution

Reduced mass =m×2mm+2m=2m3= \frac{m \times 2m}{m + 2m} = \frac{2m}{3}