Question

The rectangular coil having 100 turns is turned in a uniform magnetic field of $\frac { 0.05 } { \sqrt { 2 } } \hat { j }$Tesla as shown in the figure. The torque acting on the loop.

• A. 11.32 x 10^-4 (N-m) $\hat { \boldsymbol { k } }$
• B. 22.64 x 10^-4(N-m) $\hat { \boldsymbol { k } }$
• C. 5.66 x 10^-5 (N-m) $\hat { \boldsymbol { k } }$
• D. Zero

Answer 1

Answer: (C)

5.66 x 10^-5 (N-m) $\hat { \boldsymbol { k } }$

Answer 2

The magnetic dipole moment of the current carrying coil is given by

= 100 × 0.5 × (0.08 ) × 0.04 î = 16 × 10^-2 Am² (î)

The torque acting on the coil is

$= m B ( \hat { i } \times \hat { j } )$

= 5.66 × 10^-5 (N - m) $\hat { k }$ . Hence (3) is correct.