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Question

Physics Question on momentum

The recoil velocity of a 4.0kg4.0\, kg rifle that shoots a 0.050kg0.050\, kg bullet at a speed of 280 ms1280\text{ }m{{s}^{-1}} is:

A

+3.5 ms1+3.5\text{ }m{{s}^{-1}}

B

3.5 ms1-3.5\text{ }m{{s}^{-1}}

C

(3.5) ms1-\sqrt{(3.5)}\text{ }m{{s}^{-1}}

D

+(3.5) ms1+\sqrt{(3.5)}\text{ }m{{s}^{-1}}

Answer

3.5 ms1-3.5\text{ }m{{s}^{-1}}

Explanation

Solution

m1u1+m2u2=0{{m}_{1}}{{u}_{1}}+{{m}_{2}}{{u}_{2}}=0 \Rightarrow u1=m2u2m1{{u}_{1}}=-\frac{{{m}_{2}}{{u}_{2}}}{{{m}_{1}}} =0.050×2804=3.5ms1=\frac{0.050\times 280}{4}=-3.5\,m{{s}^{-1}}