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Question

Mathematics Question on Differential equations

The real value of ‘α’ for which 1isinα1+2isinα\frac{1 -isinα}{1+ 2isinα} is purely real is

A

(n+1)π2,nN(n+1) \frac{\pi}{2}, n ∈ N

B

(2n+1)π2,nN(2n+1) \frac{\pi}{2}, n ∈ N

C

nπ,nNn{\pi}, n ∈ N

D

(2n1)π2,nN(2n-1) \frac{\pi}{2}, n ∈ N

Answer

nπ,nNn{\pi}, n ∈ N

Explanation

Solution

The correct answer is Option (C) : nπ,nNn{\pi}, n ∈ N