Question

The real part of $x = 1,y = - 3$ is equal to.

• A. 1/4
• B. ½
• C. tan θ/2
• D. 1/1– cos θ

Answer 1

Answer: (B)

½

Answer 2

$\lbrack R_{1} \rightarrow R_{1} + R_{2}\rbrack(6i + 4)(3i^{2} + 3)$

$x + iy$ $(6i + 4)( - 3 + 3) = x + iy$

$x + iy = 0 = 0 + i.0$

Therefore its real part

= $(x,y) = (0,0)$.