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Question

Question: The real part of \(\frac{(1 + i)^{2}}{3 - i}\) is equal to...

The real part of (1+i)23i\frac{(1 + i)^{2}}{3 - i} is equal to

A

1/5

B

1/3

C

–1/3

D

None of these

Answer

None of these

Explanation

Solution

Sol. (1+i)23i=2+6i10=15+35i\frac{(1 + i)^{2}}{3 - i} = \frac{- 2 + 6i}{10} = - \frac{1}{5} + \frac{3}{5}i