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Question

Physics Question on Current electricity

The reading of voltmeter in the circuit shown is

A

2.25 V

B

3.25 V

C

4.25V

D

6.25V

Answer

2.25 V

Explanation

Solution

The correct answer is Option A) 2.25 V

From the figure, the resistance of 60 Ω\Omega of the resistor and resistance 40 Ω\Omega of the voltmeter are in parallel.

Therefore the equivalent resistance of these two resistances in parallel is given by

Req =60×4060+40=60×40100=24Ω=\frac{60\times40}{60+40}=\frac{60\times40}{100}=24\,\Omega

The total current in the circuit is given by,

I =6V(40+24)Ω=664=332A=\frac{6\,V}{\left(40+24\right)\,\Omega}=\frac{6}{64}=\frac{3}{32}\,A

The voltmeter reads potential differences across the resistance 60 Ω\Omega connected in parallel to it. Therefore using Ohm's law, the potential across the voltmeter is given by

\therefore\quad Voltmeter reading = I×ReqI\times R_{eq} =332×24=94V=2.25V=\frac{3}{32}\times24=\frac{9}{4}V=2.25\,V

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