Question

The reading of the ideal ammeter will be : (Resistance of ideal ammeters is zero )

• A. 5/6 Ampere
• B. 6/5 Ampere
• C. 3/2 Ampere
• D. 2/3 Ampere

Answer 1

Answer: (A)

5/6 Ampere

Answer 2

R_eq = 3||6 and series will 2 = 2 + 2 = 4 Ω

I = $\frac{V}{R_{eq}}$ = $\frac{10}{4}$ = $\frac{5}{2}$Amp.(current from Battery)

∴ I₁ = $\frac{I \times R_{2}}{R_{1} + R_{2}}$ = $\frac{I \times 3}{9}$ = $\frac{5}{2 \times 3}$ = 5/6 amp