Question

The reading of the ammeter shown in the figure is?

$(A)6.56{\text{ }}A$
$(B)3.28{\text{ }}A$
$(C)2.18{\text{ }}A$
$(D)1.09{\text{ }}A$

Answer 1

An ammeter (A) is linked in series to measure current. In this circuit, the meter receives all of the currents. Here, we have to find the value of ammeter reading. Because of finding its value, we should know about the formula for current. As we are applying the value of Voltage and resistance value in the current equation we will get a result which is known as a value of ammeter reading.

Formula used:
$I = \dfrac{V}{R}$

Complete step by step solution:
The circuit illustrated in the figure can simplify from the supplied circuit.
The circuit's corresponding resistance is:
${R_{eq}} = \dfrac{{2 \times 4}}{{2 + 4}} + 0.8$
As we are calculating this value,
We will get the value of ${R_{eq}}$,
${R_{eq}} = 2.13\Omega$
Applying this ${R_{eq}}$ value is given formula $I = \dfrac{V}{R}$.
Therefore,
The circuit will draw the following current:
$I = \dfrac{{14}}{{2.13}}$
By dividing this equation, the $I$value will be,
$\Rightarrow 6.56A$
The current going through the ammeter is now calculated as follows:
${I_A} = I \times \dfrac{2}{{2 + 4}}$
As we are applying $I$ value in the above equation we will get,
${I_A} = 6.56 \times \dfrac{2}{6}$
Calculated this formation We will receive the value of ${I_A}$ is,
${I_A} = 2.18A$
Hence, Option (C) is the correct answer.

Note: An ammeter is a device that measures direct or alternating electric current in amperes. An ammeter can measure a wide range of current values since only a small portion of the current is routed through the meter mechanism at high current values. A shunt running parallel to the meter carries the majority of the current.