Question

The reaction quotient $( Q )$ for the reaction: $N _{2}( g )+3 H _{2}( g ) \rightleftharpoons 2 NH _{3}( g )$ is given by $Q =\frac{\left[ NH _{3}\right]^{2}}{\left[ N _{2}\right]\left[ H _{2}\right]^{3}} .$ The reaction will proceed from right to left if :

• A. $Q = K_C$
• B. $Q < K_C$
• C. $Q > K_C$
• D. $Q = 0$

Answer 1

Answer: (C)

$Q > K_C$

Answer 2

For reaction, ${{N}_{2}}(g)+3{{H}_{2}}(g)\rightleftharpoons 2N{{H}_{3}}(g)$ $Q$ (Quotient) = $\frac{{{[N{{H}_{3}}]}^{2}}}{[{{N}_{2}}]\,{{[{{H}_{2}}]}^{3}}},\Delta n=2-4=-2$ At equilibrium $Q$ is equal to ${{K}_{C}}$ but for the progress of reaction towards right side $Q>{{K}_{C}}$ where ${{K}_{C}}$ is the equilibrium constant.